The board / graph theory / #147
Erdős Problem #147
DISPROVED LEANdatabase updated 2026-08-24
The statement as posed is false. A solution has also been checked by machine, in Lean.
What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).
If \(H\) is bipartite with minimum degree \(r\) then there exists \(\epsilon=\epsilon(H)>0\) such that \[\mathrm{ex}(n;H) \gg n^{2-\frac{1}{r-1}+\epsilon}.\] Conjectured by Erdős and Simonovits [ErSi84]. A probabilistic argument shows that there exists some \(\epsilon=\epsilon(H)>0\) such that \(\mathrm{ex}(n;H) \gg n^{2-\frac{2}{r}+\epsilon}\). This conjecture was disproved by Janzer [Ja23] for even \(r\geq 4\). The case \(r=3\) was disproved by Janzer [Ja23b], who constructed, for any \(\epsilon>0\), a \(3\)-regular bipartite graph \(H\) such that \(\mathrm{ex}(n;H)\ll n^{\frac{4}{3}+\epsilon}\). In [Ja23] Janzer conjectures that the above lower bound is sharp, in that for any \(r\geq 3\) and \(\epsilon>0\) there exists an \(r\)-regular graph \(H\) such that \(\mathrm{ex}(n;H) \ll n^{2-\frac{2}{r}+\epsilon}\). Janzer's result proves this for even \(r\geq 4\). See also [113](https://www.erdosproblems.com/113), [146](https://www.erdosproblems.com/146), and [714](https://www.erdosproblems.com/714). The conjecture is stated for minimum degree \(r \geq 2\) (for \(r = 1\) the exponent \(2 - \frac{1}{r-1}\) is not meaningful).
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved · 3 further variants / known partial results in the Lean file. The authoritative wording is on erdosproblems.com/147.Prize$500
Topicsgraph theory, turan number
Statement in LeanFormal Conjectures
Solution in Leanyes
Original pageerdosproblems.com/147
Attempts
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