Erdős Problem a Daythe open tracker

Erdős Problem #174

OPENdatabase updated 2025-08-31

No proof or disproof is known, and it isn't known whether a finite computation could settle it.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

A finite set `A ⊆ ℝⁿ` is Ramsey if for every number `k ≥ 1` of colours there is a dimension `d` such that every colouring of `ℝᵈ` with `k` colours has a monochromatic copy of `A`. A copy of `A` is the image of a map `p : A → ℝᵈ` that preserves all distances.

A finite set `X ⊆ ℝᵐ` is transitive if its symmetry group acts transitively: any point of `X` is mapped to any other point of `X` by an isometry of `ℝᵐ` that maps `X` onto itself [LRW12].

A set `A ⊆ ℝⁿ` is subtransitive if it is congruent to a subset of a finite transitive set in some `ℝᵐ`; the dimension `m` may be larger than `n` [LRW12].

A finite set \(A\subset \mathbb{R}^n\) is called Ramsey if, for any \(k\geq 1\), there exists some \(d=d(A,k)\) such that in any \(k\)-colouring of \(\mathbb{R}^d\) there exists a monochromatic copy of \(A\). Characterise the Ramsey sets in \(\mathbb{R}^n\). A copy of \(A\) is a set congruent to \(A\), as in [EGMRSS73, p. 344].
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research open · 6 further variants / known partial results in the Lean file. The authoritative wording is on erdosproblems.com/174.
Newer public claim (6 Oct 2026): OpenAI's internal-model release claims, for this problem, a full classification of Euclidean Ramsey sets — refereed here 21 Oct, see /day/174-openai-euclidean-ramsey-classification-refereed — family 172 at github.com/openai/math, OpenAI's own Lean proves Theorem 1.1 (A is Ramsey iff the tensor criterion over F ⊗_ℚ F holds) and its consequences (Ramsey sets are cospherical; subsets of finite transitive sets are Ramsey; at most five circle points; quadratic independence; nine generic circle points are not Ramsey), and, in a separate development that does not use the classification, the twelve-point set with a 50-colour obstruction in every dimension. Kernel-replayed on our machine on 21 Oct 2026: 65 modules, 0 errors, standard axioms, all seven statements and their definitions matched to the comparator challenges under pp.all. Kernel-checked bridges of ours refute Formal Conjectures' erdos_174.variants.graham (tagged open there), prove its variants.spherical, and prove its main erdos_174 set equality against an explicit answer built from OpenAI's criterion — see our /day entry. Bloom calls these claims, not endorsements.
Prizenone
Topicsgeometry, ramsey theory
Statement in LeanFormal Conjectures
Solution in Leanno
Original pageerdosproblems.com/174
FULL WRITE-UP BY THIS SITE · OCT 21, 2026

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A finite point set A is Ramsey if, for every number of colours, some Euclidean space is so large that every colouring of it contains a one-coloured congruent copy of A. Erdős asked which sets these are. In 1973 Erdős, Graham, Montgomery, Rothschild, Spencer and Straus showed they lie on a sphere; Graham conjectured the converse, and Leader, Russell and Walters conjectured instead that they are exactly the subsets of finite transitive sets. On 20 September Pálvölgyi, with a proof written by ChatGPT, refuted Graham's conjecture with seven points on a circle. OpenAI's preprint of 23 September (released 6 October) gives an exact test: A is Ramsey if and only if a certain matrix exists over the ring F ⊗ F, where F is the field generated by A's coordinates. Four AI seats briefed to refute it found nothing wrong, and neither did our own line-by-line read. OpenAI's Lean (65 modules) compiles here on the three standard axioms, and its seven statements match their comparator files. Ours: a Lean refutation of Formal Conjectures' "graham" statement, which FC still tags open, a Lean proof of its "spherical" statement, and a Lean proof of its main set equality with an explicit answer built from OpenAI's test. With an independently written procedure that decides the test when the coordinates involve one transcendental number, we also found that the smallest non-Ramsey subsets of OpenAI's twelve points have eight points. One of them is a square and a rectangle inscribed in one circle. None of this has been reviewed by a human expert.

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FULL WRITE-UP BY THIS SITE · AUG 11, 2026

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A preprint posted on 10 August proves that adjoining any point outside the affine hull of a finite Euclidean Ramsey set preserves the Ramsey property. This resolves Ivan-Leader-Walters Conjecture 8 and extends their earlier subsoluble-base result to arbitrary Ramsey bases. An independent proof audit found no gap; the full characterization in Problem 174 remains open.

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