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Erdős Problem #391

PROVED LEANdatabase updated 2026-08-24

The statement as posed is true, and a proof exists. A solution has also been checked by machine, in Lean.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

`t n` is the largest `t` such that `n!` is a product of `n` factors all at least `t`, i.e. the maximal \(a_1\) in a representation \(n! = a_1 \cdots a_n\) with \(a_1 \leq \cdots \leq a_n\).

Let \(t(n)\) be maximal such that there is a representation \[n!=a_1\cdots a_n\] with \(t(n)=a_1\leq \cdots \leq a_n\). Obtain good bounds for \(t(n)/n\). In particular, is it true that \[\lim \frac{t(n)}{n}=\frac{1}{e}?\] It is easy to see that \(\lim \frac{t(n)}{n}\leq \frac{1}{e}\). Erdős [Er96b] wrote he, Selfridge, and Straus had proved a corresponding lower bound, so that \(\lim \frac{t(n)}{n}=\frac{1}{e}\), and 'believed that Straus had written up our proof. Unfortunately Straus suddenly died and no trace was ever found of his notes. Furthermore, we never could reconstruct our proof, so our assertion now can be called only a conjecture.' Alladi and Grinstead [AlGr77] have obtained similar results when the \(a_i\) are restricted to prime powers. Both questions were answered by Alexeev, Conway, Rosenfeld, Sutherland, Tao, Uhr, and Ventullo [ACRSTUV25], who proved that \[\frac{t(n)}{n}= \frac{1}{e}-\frac{c_0}{\log n}+O\left(\frac{1}{(\log n)^{1+c}}\right),\] where \(c_0=0.3044\cdots\) is an explicit constant, for some \(c>0\).
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved · 1 further variant / known partial result in the Lean file. The authoritative wording is on erdosproblems.com/391.
Prizenone
Topicsnumber theory, factorials
Statement in LeanFormal Conjectures
Solution in Leanyes
OEISA034258, A034259
Original pageerdosproblems.com/391
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