Erdős Problem a Daythe open tracker

Erdős Problem #551

DECIDABLEdatabase updated 2025-08-31

Still open, but reduced to a finite computation: checking enough cases would settle it either way.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

Prove that \[R(C_k,K_n)=(k-1)(n-1)+1\] for \(k\geq n\geq 3\) (except when \(n=k=3\)). Asked by Erdős, Faudree, Rousseau, and Schelp. This problem is #18 in Ramsey Theory in the graphs problem collection.
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research open · 1 further variant / known partial result in the Lean file. The authoritative wording is on erdosproblems.com/551.
Newer public claim (6 Oct 2026): OpenAI's internal-model release claims, for this problem, R(C_m, K_n) = (m−1)(n−1)+1 for all m ≥ n ≥ 3 except (3,3) — refereed here 20 Oct, see /day/551-openai-cycle-clique-ramsey-refereed — family 189 at github.com/openai/math, OpenAI's own Lean proves Theorem 1.1 — R(C_m,K_n) = (m−1)(n−1)+1 for all m ≥ n ≥ 3 except (3,3), and R(C_3,K_3) = 6 — and the comparator theorem's closure (182 modules) was kernel-replayed on our machine on 20 Oct 2026: 0 errors, standard axioms, statement matched to the challenge under pp.all, leanchecker --fresh over the whole closure rc 0; a kernel-checked bridge of ours derives a verbatim copy of Formal Conjectures' erdos_551 from it — see our /day entry. Bloom calls these claims, not endorsements.
Prizenone
Topicsgraph theory, ramsey theory
Statement in LeanFormal Conjectures
Solution in Leanno
Original pageerdosproblems.com/551
FULL WRITE-UP BY THIS SITE · OCT 20, 2026

Read our full write-up →

Erdős, Faudree, Rousseau and Schelp conjectured in 1978 that R(C_m, K_n) = (m−1)(n−1)+1 for all m ≥ n; in its standard form, with n ≥ 3 and (3,3) excepted, it is Erdős problem #551. Keevash, Long and Skokan proved it in 2021 for m ≥ C log n / log log n. That settles every large n but leaves finitely many pairs, and since their C is not explicit, not even the list of open pairs was known; Terence Tao noted on the problem page in September 2025 that the problem was decidable but still open. OpenAI's 6 October release claims all of it. The proof takes a minimal counterexample, finds a clique of order at least max{3, ⌊(m−1)/2⌋}, rules out cliques of order 9 or more by hand, and reduces the rest to 3,099 finite patterns of paths between clique vertices; two Python programs and, by a different encoding, a Lean proof each exclude them all. We read §§2–9 line by line and found no gap; two hostile AI referee seats on the mathematics (the t ≥ 9 argument, and the finite stage with its code) and one on the sources agreed. Our own enumerator reproduces the 3,099 patterns, both checkers re-run clean, and the Lean proof of the comparator's theorem (182 modules) replays on our machine with the standard axioms and a matching statement. A kernel-checked bridge of ours carries OpenAI's theorem to a verbatim copy of Formal Conjectures' erdos_551, which is still marked open there, with a pull request to close it waiting on a checked formal proof. Nothing in the theorem is ours.

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