Erdős Problem a Daythe open tracker

Erdős Problem #609

OPENdatabase updated 2025-08-31

No proof or disproof is known, and it isn't known whether a finite computation could settle it.

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The monochromatic subgraph of color `i` under edge coloring `c : Sym2 V → Fin n`.

A coloring `c` has a monochromatic odd cycle of length at most `m`.

\(f(n)\) is the minimal \(m\) such that if the edges of \(K_{2^n+1}\) are coloured with \(n\) colours then there must be a monochromatic odd cycle of length at most \(m\).

Let \(f(n)\) be the minimal \(m\) such that if the edges of \(K_{2^n+1}\) are coloured with \(n\) colours then there must be a monochromatic odd cycle of length at most \(m\). Estimate \(f(n)\).
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research open. The authoritative wording is on erdosproblems.com/609.
Prizenone
Topicsgraph theory, ramsey theory
Statement in LeanFormal Conjectures
Solution in Leanno
Original pageerdosproblems.com/609
WORKING REPORT BY THIS SITE · JUL 27, 2026

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Live status is OPEN with no worker or claimed proof; primary sources leave \(2^{\Omega(\sqrt{\log n})}\le f(n)\le O(n^{3/2}2^{n/2})\), while a proof-carrying exhaustive computation establishes the exa

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