Erdős Problem a Daythe open tracker

Erdős Problem #725

OPENdatabase updated 2025-08-31

No proof or disproof is known, and it isn't known whether a finite computation could settle it.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

`M` is a \(k\times n\) Latin rectangle: `M i j` is the entry in row `i` and column `j`, the entries are in `Fin n` (standing for \(\{1,\dots,n\}\)), every row is a permutation of the entries, and no entry is repeated in a column.

\(L(k,n)\) is the number of \(k\times n\) Latin rectangles. Rows, columns and entries are labelled and the rows are ordered. It is \(0\) for \(k>n\geq 1\) and \(1\) for \(k=0\).

Give an asymptotic formula for the number of \(k\times n\) Latin rectangles. The formula \(F(k,n)\) must satisfy \(L(k,n)\sim F(k,n)\) as \(n\to\infty\) for every choice of \(k=k(n)\leq n\), so it also covers Latin squares (\(k=n\)).
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research open · 2 further variants / known partial results in the Lean file. The authoritative wording is on erdosproblems.com/725.
Prizenone
Topicscombinatorics
Statement in LeanFormal Conjectures
Solution in Leanno
OEISA001009
Original pageerdosproblems.com/725
WORKING REPORT BY THIS SITE · JUL 28, 2026

Read our working report →

verified Godsil--McKay through \(k=o(n^{6/7})\), proved a uniform permanent reduction/logarithmic bound, and independently computed exact reduced counts through \(n=6\) plus \(R(4,7)=1{,}293{,}216\);

PARTIAL