Erdős Problem a Daythe open tracker

Erdős Problem #751

DISPROVED LEANdatabase updated 2026-01-27

The statement as posed is false. A solution has also been checked by machine, in Lean.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

Let \(G\) be a graph with chromatic number \(\chi(G)=4\). If \(m_1<m_2<\cdots\) are the lengths of the cycles in \(G\) then can \(\min(m_{i+1}-m_i)\) be arbitrarily large? The answer is no: Bondy and Vince [BoVi98] proved that every graph with minimum degree at least \(3\) has two cycles whose lengths differ by at most \(2\), and hence the same is true for every graph with chromatic number \(4\). `erdos_751.variants.finite` below carries the Lean proof. It assumes a finite vertex type, where this quantifies over any `V : Type`, and the two are joined by de Bruijn-Erdős: a graph that is not \(3\)-colourable has a finite subgraph that is not \(3\)-colourable, and cycles of that subgraph are cycles of the whole. Mathlib does not have de Bruijn-Erdős, so that step is not formalised here.
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved · 3 further variants / known partial results in the Lean file. The authoritative wording is on erdosproblems.com/751.
Prizenone
Topicsgraph theory, chromatic number
Statement in LeanFormal Conjectures
Solution in Leanyes
Original pageerdosproblems.com/751
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