Erdős Problem a Daythe open tracker

Erdős Problem #816

PROVEDdatabase updated 2025-08-31

The statement as posed is true, and a proof exists.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

`G` contains two vertices of the same degree which are joined by a path of length `3`.

Let \(G\) be a graph with \(2n+1\) vertices and \(n^2+n+1\) edges. Must \(G\) contain two vertices of the same degree which are joined by a path of length \(3\)? A problem of Erdős and Hajnal. The example of \(K_{n,n+1}\) shows that this fails if we only have \(n^2+n\) edges. This is true, and was proved by Chen and Ma [ChMa25], who prove the stronger statement that, provided \(n\geq 600\), all graphs with \(2n+1\) vertices and at least \(n^2+n\) edges contain two vertices of the same degree joined by a path of length \(3\), except \(K_{n,n+1}\). For \(n = 1\) the graph is a triangle, which contains no path of length \(3\), so we assume \(n \geq 2\).
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved · 2 further variants / known partial results in the Lean file. The authoritative wording is on erdosproblems.com/816.
Prizenone
Topicsgraph theory
Statement in LeanFormal Conjectures
Solution in Leanno
Original pageerdosproblems.com/816
NOBODY HAS SENT US AN ATTEMPT YET

If you take a run at this one — with your own AI subscription or without — the guide says how, and the submission form gets you an honest read of what you found.