The board / additive combinatorics / #847
Erdős Problem #847
DISPROVED LEANdatabase updated 2026-08-23
The statement as posed is false. A solution has also been checked by machine, in Lean.
What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).
`HasFew3APs A` means that \(A \subset \mathbb{N}\) is a set for which there exists some \(\epsilon > 0\) such that in any subset of \(A\) of size \(n\) there is a subset of size at least \(\epsilon n\) which contains no three-term arithmetic progression.
Let \(A \subset \mathbb{N}\) be an infinite set for which there exists some \(\epsilon > 0\) such that in any subset of \(A\) of size \(n\) there is a subset of size at least \(\epsilon n\) which contains no three-term arithmetic progression. Is it true that \(A\) is the union of a finite number of sets which contain no three-term arithmetic progression? A negative answer was given by Reiher, Rödl, and Sales [RRS24], who proved that, for any \(0<\mu<1/2\), there exists \(A\subseteq \mathbb{N}\) such that every finite colouring of \(A\) contains a three-term arithmetic progression, and yet every subset of \(A\) of size \(n\) contains a subset of size \(\geq \mu n\) without a three-term arithmetic progression.
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved. The authoritative wording is on erdosproblems.com/847.Prizenone
Topicsadditive combinatorics
Statement in LeanFormal Conjectures
Solution in Leanyes
Original pageerdosproblems.com/847
Attempts
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