The board / arithmetic progressions / #196
Erdős Problem #196
OPENdatabase updated 2025-08-31
No proof or disproof is known, and it isn't known whether a finite computation could settle it.
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Must every permutation of \(\mathbb{N}\) contain a monotone 4-term arithmetic progression? Here a monotone \(k\)-term arithmetic progression in a permutation \(f\) is a set of indices \(i_1 < \cdots < i_k\) such that \(f(i_1), \ldots, f(i_k)\) is an increasing or decreasing arithmetic progression. [DEGS77] showed that every permutation of \(\mathbb{N}\) contains a monotone 3-term arithmetic progression, and that there are permutations with no monotone 5-term arithmetic progression. The answer is no: [Ho26] constructs an explicit permutation of the positive integers with no monotone 4-term arithmetic progression. Independent constructions with Lean formalizations were given shortly afterwards by Kruer and Kohlmeyer and, pseudonymously, in the repository `coleski/erdos196`; the linked formal proof establishes the negation of this statement.
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved. The authoritative wording is on erdosproblems.com/196.Prizenone
Topicsarithmetic progressions
Statement in LeanFormal Conjectures
Solution in Leanno
Original pageerdosproblems.com/196
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Three exact enumerations give theta_4(13)=949,812,334 and theta_4(14)=9,471,574,188. The known table through n=12 is independently reproduced. This is a finite counting extension only; the singly infinite permutation problem remains open.
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