ERDŐS/DAILY

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ERDőS #1210 · PARTIAL

Erdős problem #1210 — wave 8k

Access/check date: 2026-07-28 UTC.

Outcome

The problem remains open. This run gives two independently checkable pieces

of progress.

1. (a) Elementary-rigorous: an exact radical-support compression formula

for the finite extremal quantity \(M(n)\). It turns the optimization over

all pairwise-coprime subsets of \([1,n)\) into a weighted set-packing

problem involving only profitable composite replacements of a canonical

prime-power baseline.

2. **(d) Computational-only for the finite optimality claims; (a) for

exhaustiveness and every displayed witness:** exact rational computation

for every \(2\leq n\leq1000\). In this complete range,

\[ M(n)\leq \sum_{p

and the constant \(1\) is sharp, with equality exactly for

\(n=2,3,4,6\). For \(16\leq n\leq1000\), the largest defect occurs at

\(n=204\) and is

\[ \frac{ 79238096535390154478342194618765038722392907207825438 }{ 81727606403062853596766096017766921944452742445065375 } =0.969538935774\ldots. \]

This is not a uniform proof. The exact remaining obstruction is a uniform

bound on a weighted positive packing defect; even its prime-only part contains

the shifted short-interval problem highlighted on the live page and in the

recent literature.

0. Mandatory live-page gate

I used the Bright Data cloud-browser path to read the rendered live pages:

I did not rely on datacenter curl or on the stale tracker YAML.

Live status and markers

(d: direct browser observation) The rendered page displayed:

The page said it was last edited 08 April 2026. Thus neither mandatory stop

condition was present.

Verbatim current statement

The following is copied verbatim from the current LaTeX-source page:

Let $A\subseteq [1,n)$ be a set of integers such that $(a,b)=1$ for all distinct $a,b\in A$. Is it true that
\[\sum_{a\in A}\frac{1}{n-a}\leq \sum_{p<n}\frac{1}{p}+O(1)?\]

(a, using the original 1980 wording below) The \(O(1)\) is an absolute

constant, uniform in \(n\) and in the admissible set \(A\).

Other information printed on the problem page

The page gives references [Er77c,p.64][Er80,p.112], the tag number theory,

and this historical note:

> In [Er80] he claims he 'did not state [this] quite correctly' in [Er77c].

> The problem in [Er77c] which Erdős is presumably referring to states that

> if \(n

> \[ > \sum \frac{1}{q_i-n}<\sum_{p \]

> See also [460] and [950].

The page itself lists no proved bound for #1210.

All three live comments

**(d: browser transcription; none is treated as a theorem merely because it

is a comment)**

1. ebarschkis, 31 May 2026: “This paper claims a few interesting results

on this problem, but no full solution.” “This paper” links to Idriss

Olivier Bado's May 2026 ResearchGate preprint checked below.

2. Thomas Bloom, 08 April 2026: reported a GPT suggestion that it should

suffice to prove

\[ |A\cap[n-x,n)|\leq \pi(x)+O\!\left(\frac{x}{(\log x)^2}\right), \]

initially suggested charging elements having a prime factor \(

then edited the comment to express scepticism because \(A\) can contain

many primes in the shifted window; the comment points to #855.

3. Nat Sothanaphan, 08 April 2026: agreed that the proposed estimate does

not follow from standard sieve theory, since it would imply

\[ \pi(x+y)\leq\pi(x)+\pi(y) +O\!\left(\frac{y}{(\log y)^2}\right), \]

one of the conjectural estimates discussed at #855.

The forum explicitly warns that comments are unverified. There was no

claimed-proof post and no current-worker marker.

1. Primary-source and literature checks

Erdős's original sources

(d: primary-document check) The Rényi archive contains both sources cited

on the live page.

1. P. Erdős, Problems and results on combinatorial number theory. III,

Lecture Notes in Mathematics 626 (1977), 43–72,

<https://www.renyi.hu/~p_erdos/1977-27.pdf>.

On printed page 64 it gives the earlier conjecture for primes

\(n

live page.

2. P. Erdős, A survey of problems in combinatorial number theory, Annals of

Discrete Mathematics 6 (1980), 89–115,

<https://www.renyi.hu/~p_erdos/1980-03.pdf>.

On printed page 112 it says, “Here is a problem which I did not state quite

correctly in III,” takes

\(1\leq a_1<\cdots

absolute \(C\) such that

\[ \sum_{i=1}^k\frac1{n-a_i} < C+\sum_{p

Thus the modern statement and the intended uniformity agree with the primary

1980 source.

May 2026 dyadic/Farey preprint

**(d for bibliographic verification; b modulo the preprint's standard-sieve

input)** The paper linked by the first comment exists:

I. O. Bado, *A Dyadic-Farey Reduction for an Erdős Problem on Pairwise

Coprime Sets*, May 2026,

DOI <https://doi.org/10.13140/RG.2.2.33043.03361>,

full record

<https://www.researchgate.net/publication/405212040_A_Dyadic-Farey_Reduction_for_an_Erdos_Problem_on_Pairwise_Coprime_Sets>.

It explicitly says it does not claim a full proof. Its stated results are:

\(M(n)\ll\log\log n\);

shifted-prime comparisons;

The paper identifies sharp rough-number counts and shifted primes as the

remaining obstruction.

June 2026 average-order preprint not yet on the live page

**(d for bibliographic and theorem-statement verification; b modulo the

preprint's Buchstab and beta-sieve arguments)** Exact-problem searches found a

newer, directly relevant primary artifact:

E. Li, *An Average-Order Theorem for a Shifted Pairwise-Coprime Extremal

Problem*, arXiv:2606.17955v1, submitted 16 June 2026,

<https://arxiv.org/abs/2606.17955>.

The 36-page preprint defines exactly the same \(M(n)\) and claims:

\[ \sum_{n\leq N}M(n) =e^{-\gamma}N\log\log N+O(N); \]

\[ M(n)=(e^{-\gamma}+o(1))\log\log n, \]

with a quantitative exceptional-set bound, hence the Erdős inequality for a

density-one set of \(n\);

\[ M(n)\leq(2+\varepsilon)\log\log n+C_\varepsilon \quad(n\geq3); \]

and small exact examples at \(n=16,20,30\).

I verified that the arXiv identifier, author, submission date, full text, and

these theorem statements exist. I did not independently audit every

analytic-sieve step in the preprint, so these are recorded as preprint claims,

not as new theorems of this run. They are partial results and do not settle

the uniform constant-\(1\) question.

Literature-search miss

(c, deliberately not a theorem) Exact-statement, exact-title, arXiv, and

general web searches found the two 2026 preprints above and the original

sources, but no primary source claiming a full uniform proof or

counterexample. I also found no independent review or citation of the June

preprint. This is a report of the searches performed, not a claim that no

other relevant work exists.

2. Exact radical-support compression

Define

\[ \operatorname{supp}(a)=\{p:p\mid a,\ p\text{ prime}\}. \]

For every nonempty prime set \(S\) which occurs as a support below \(n\), put

\[ m_n(S)=\max\{aFor a prime \(p \[ u_p(n):=m_n(\{p\})=\max\{p^k:p^kFor \(|S|\geq2\), define its replacement gain

\[ \Delta_n(S)=w_n(S)-\sum_{p\in S}w_n(\{p\}). \]

Let

\[ \mathcal C_n=\{S:|S|\geq2,\ m_n(S)\text{ exists},\ \Delta_n(S)>0\}, \]

and let the exact packing premium be

\[ P(n)= \max_{\substack{\mathcal F\subseteq\mathcal C_n\\ S\cap T=\varnothing\ (S\ne T)}} \sum_{S\in\mathcal F}\Delta_n(S). \]

Compression theorem

(a) Elementary-rigorous. For every integer \(n\geq2\),

\[ \boxed{ M(n)= \frac1{n-1} +\sum_{pProof

1. The element \(1\) is coprime to everything and has positive weight, so it

occurs in every maximizer. It contributes \(1/(n-1)\).

2. For \(a,b>1\), \((a,b)=1\) exactly when

\(\operatorname{supp}(a)\cap\operatorname{supp}(b)=\varnothing\).

Hence an admissible set is a family of disjoint prime supports, with at

most one integer per support.

3. For a fixed support \(S\), the weight \(1/(n-a)\) strictly increases with

\(a\). Thus only \(m_n(S)\), the largest integer with that support, can

occur in a maximizer.

4. If no chosen nonsingleton support uses \(p\), the singleton

\(u_p(n)\) can be added. Therefore every maximizer is a canonical baseline

\[ \{1\}\cup\{u_p(n):p

with some disjoint groups of singleton supports replaced by their

nonsingleton \(m_n(S)\).

5. Replacing the singleton group \(S\) changes the weight by exactly

\(\Delta_n(S)\). A nonpositive-gain replacement can be undone without

affecting any other chosen support. Thus only \(\mathcal C_n\) matters,

and maximizing the sum of disjoint positive gains gives (2.1). \(\square\)

Safe dominance used in the computation

(a) Elementary-rigorous. If \(T\subseteq S\) and

\(\Delta_n(T)\geq\Delta_n(S)\), candidate \(S\) may be deleted. Any packing

using \(S\) remains feasible after replacing it by \(T\), uses no new prime,

and does not lose weight. This is the only nontrivial pruning applied before

the exhaustive recurrence.

(c) I did not find formula (2.1) stated in the checked sources. This is a

search impression, not a priority or novelty claim.

3. Exact analytic reduction and the prime obstruction

For an admissible \(A\), let \(N=n-1\) and

\[ B_{A,n}(m)=|\{a\in A:n-a\leq m\}|. \]

Discrete summation by parts gives the exact identity

\[ \sum_{a\in A}\frac1{n-a} =\frac{B_{A,n}(N)}N \sum_{m=1}^{N-1}\frac{B_{A,n}(m)}{m(m+1)}. \]

Applying the same identity to the distances which are primes gives

\[ \boxed{ \sum_{a\in A}\frac1{n-a}-\sum_{p(a) This is an exact finite identity; the verifier checks both sides for

every computed extremizer and for the prime benchmark.

A uniform bound

\[ B_{A,n}(m)\leq \pi(m)+C\frac{m}{(\log m)^{1+\delta}} \quad(m\geq3) \tag{3.2} \]

for any fixed \(\delta>0\) would make the positive error in (3.1) summable and

would prove #1210.

(a) Exact obstruction to treating (3.2) as a routine sieve estimate.

Take \(A\) to be all primes below \(n=x+y\) and set \(m=y\). Then (up to

harmless endpoint changes)

\[ B_{A,n}(y)=\pi(x+y)-\pi(x). \]

Consequently (3.2) would imply

\[ \pi(x+y)\leq\pi(x)+\pi(y) +O\!\left(\frac{y}{(\log y)^{1+\delta}}\right). \]

For \(\delta=1\), this is precisely the implication identified in the live

comments. Thus the proposed window bound already contains a conjectural

short-interval prime statement; pairwise coprimality supplies no extra help

when \(A\) itself is the prime set.

Formula (2.1) exposes the same issue differently. If \(p>\sqrt n\), then

\(u_p(n)=p\), so its baseline contains

\[ \sum_{\sqrt n(a) Hence even before any profitable composite replacement is considered,

a uniform proof must control a shifted-prime harmonic tail. The exact

remaining task in the compressed model is

\[ \frac1{n-1} +\sum_{puniformly in \(n\). Standard one-dimensional upper-bound sieve estimates

give the right \(\log\log n\) order but, as the checked preprints explain,

lose the sharp leading constant.

4. Exact computation for \(2\leq n\leq1000\)

Algorithm and why it is exhaustive

(a) A smallest-prime-factor sieve computes every

\(\operatorname{supp}(a)\). Formula (2.1) constructs all positive-gain

candidates, and the safe dominance rule removes only provably redundant

ones. A candidate is represented by the bit mask of its prime support.

For an active candidate set \(C\), choose any \(i\in C\). Every optimal

packing is in exactly one of the following branches:

\[ F(C)=\max\left( F(C\setminus\{i\}), \ \Delta_i+F(C\setminus N[i]) \right), \tag{4.1} \]

where \(N[i]\) is \(i\) together with all candidates sharing a prime with it.

Disconnected conflict components are additive. Memoizing (4.1) is an

exhaustive exact algorithm, not a heuristic or floating-point MILP.

(d) All weights and comparisons use Python Fraction. For every output

row the program independently:

  • reconstructs a maximizing set \(A\);
  • checks every pairwise gcd;
  • recomputes its exact reciprocal sum;
  • recomputes the prime benchmark and self-rough sum;
  • checks the discrete partial-summation identities;
  • checks that the self-rough family has disjoint prime supports.

For \(2\leq n\leq40\), a second optimizer ignores the compression entirely:

it processes every original integer \(2\leq a

best exact weight for every used-prime mask. It agrees with (4.1) in every

case. The program also reproduces the exact \(n=16,20,30\) examples in Li's

preprint.

Complete finite-range statement

(d for optimality; a for exhaustive recurrence and arithmetic checking).

For every \(2\leq n\leq1000\),

\[ M(n)-\sum_{pEquality occurs exactly at

\[ n\in\{2,3,4,6\}. \]

For \(16\leq n\leq1000\), the exact maximum defect is the fraction displayed

in the Outcome and is attained at \(n=204\).

At \(n=204\), a compact description of the maximizing set is:

  • start with \(1\) and \(u_p(204)\), the largest power of each prime

\(p<204\);

  • replace the ten singleton supports involved in

\[ \{5,37\},\{11,17\},\{3,67\},\{2,101\},\{7,29\} \]

by \(185,187,201,202,203\), respectively.

The resulting explicit witness is

\[ \begin{split} A=\{& 1,19,23,31,41,43,47,53,59,61,71,73,79,83,89,97,\\ &103,107,109,113,127,131,137,139,149,151,157,163,167,169,\\ &173,179,181,185,187,191,193,197,199,201,202,203 \}. \end{split} \]

(a) Its pairwise coprimality and weight are directly checkable. Its exact

weight is

\[ M(204)= \frac{ 49435925922502585453897593152247276774288469 }{ 16938389322869963740970520244226744041371750 } =2.918573010703\ldots. \]

(d) Recurrence (4.1) certifies that no admissible set has larger weight.

Verified checkpoint table

All displayed decimals are rounded from exact Fraction values. Here

\[ H_P(n)=\sum_{pand

\[ L(n)=\sum_{\substack{1\leq dd}}\frac1d \]

is the self-rough lower weight used in the June preprint.

| \(n\) | \(M(n)\) | \(H_P(n)\) | \(D(n)\) | \(L(n)\) |

|---:|---:|---:|---:|---:|

| 2 | 1.000000000000 | 0.000000000000 | 1.000000000000 | 1.000000000000 |

| 3 | 1.500000000000 | 0.500000000000 | 1.000000000000 | 1.500000000000 |

| 4 | 1.833333333333 | 0.833333333333 | 1.000000000000 | 1.333333333333 |

| 5 | 1.750000000000 | 0.833333333333 | 0.916666666667 | 1.750000000000 |

| 10 | 2.144444444444 | 1.176190476190 | 0.968253968254 | 1.444444444444 |

| 16 | 2.100000000000 | 1.344022644023 | 0.755977355977 | 1.600000000000 |

| 20 | 2.283522909839 | 1.455477752382 | 0.828045157457 | 1.639933166249 |

| 30 | 2.489960511002 | 1.533438771872 | 0.956521739130 | 1.345172069310 |

| 50 | 2.477149638581 | 1.661646517016 | 0.815503121565 | 1.784883454056 |

| 100 | 2.548257374513 | 1.802817201049 | 0.745440173464 | 1.713916702623 |

| 200 | 2.710598365387 | 1.949034074929 | 0.761564290459 | 1.964320336962 |

| 500 | 2.881461750818 | 2.096709552839 | 0.784752197980 | 2.099980032015 |

| 1000 | 3.021272204117 | 2.198080127175 | 0.823192076942 | 2.059549363908 |

The five largest defects in \(16\leq n\leq1000\) are:

| rank | \(n\) | exact-computation defect |

|---:|---:|---:|

| 1 | 204 | 0.969538935774 |

| 2 | 84 | 0.958437343423 |

| 3 | 174 | 0.957807616150 |

| 4 | 504 | 0.957657656674 |

| 5 | 294 | 0.956851500994 |

The SHA-256 digest of the canonical exact rows (exact \(M,H_P,L\), compact

replacement witness, and full witness for every \(2\leq n\leq1000\)) is

988a913d8a2929a43238ad9bbc97d02a08aad7fbf39030e6a67106bfca72a2e6

5. Reproduction and code

The standalone dependency-free verifier is:

runs/erdos1210_wave8k_verify.py

Source SHA-256:

86b0ac34845d58d3a9eff3adca9f8cc0847a369434670e1c7fc3d2190c26c7d9

Run from the repository root:

PYTHONHASHSEED=271828 python runs/erdos1210_wave8k_verify.py \
  --limit 1000 --direct-up-to 40

Environment used: CPython 3.12.3. The final complete run took 47.858 seconds

on this VM and printed, in part:

DIRECT_CROSSCHECK=2..40
LITERATURE_EXAMPLES=16,20,30 MATCH (when within range)
EXACT_RANGE=2..1000
MAX_DEFECT=1/1 (1.000000000000) AT_N=[2, 3, 4, 6]
MAX_DEFECT_N_GE_16=79238096535390154478342194618765038722392907207825438/81727606403062853596766096017766921944452742445065375 (0.969538935774) AT_N=204
MAX_DEFECT_N_GE_500=733118969115751048968118684513145263833659469944488351605998795122449980610595163944099861144923070139556123371438381/765533449251710323760663599607882550042388743057861947713564920595729228607783618823470518780923893017414270940583875 (0.957657656674) AT_N=504
SHA256=988a913d8a2929a43238ad9bbc97d02a08aad7fbf39030e6a67106bfca72a2e6
ELAPSED_SECONDS=47.858

Repeated full runs, including one with the displayed hash seed, produced the

same exact-row digest.

The core recurrence in the adjacent full source is:

excluded_value, excluded_choice = solve(active & ~(1 << pivot))
included_value, included_choice = solve(active & ~conflict[pivot])
included_value += candidates[pivot].gain
included_choice |= 1 << pivot
if included_value > excluded_value:
    return included_value, included_choice
if included_value < excluded_value:
    return excluded_value, excluded_choice
return min(
    (included_value, included_choice),
    (excluded_value, excluded_choice),
    key=lambda pair: pair[1],
)

The full implementation also includes component splitting, witness

reconstruction, the independent uncompressed dynamic program, all arithmetic

checks, and the canonical digest.

6. What remains and why the standard machinery stalls

1. Uniformity. (a) No finite computation can prove (3.3) for all

\(n\). The verified \(+1\) bound through \(1000\) is a sharp theorem only

for that concrete finite range.

2. Prime-only missing lemma. (a) Any uniform local estimate strong

enough to make (3.1) summable applies to \(A=\{\text{primes}

yields a conjectural short-interval prime-counting inequality. This is an

exact implication, not merely an analogy. A successful proof would need

either that prime input or a genuinely weighted cancellation mechanism

weaker than pointwise window control.

3. Rough-composite missing lemma. (b, modulo the checked preprints)

Standard upper-bound sieves control the number of rough shifted integers

with the correct order \(D/\log D\), but not the sharp constant needed

after summing harmonic dyadic blocks. Li's preprint reaches

\(2+\varepsilon\) pointwise and constant \(e^{-\gamma}\) on average/almost

everywhere; neither supplies the uniform \(1+O(1/\log\log n)\)-scale

control implicit in #1210.

4. Exact compressed target. (a) In the new finite formula, the missing

uniform statement is exactly (3.3): jointly bound the shifted prime-power

baseline defect and the optimum disjoint positive-replacement premium

\(P(n)\). Bounding either term crudely by \(O(\log\log n)\) loses precisely

the information sought.

5. Computation cost. (d) The full \(n\leq1000\) sweep took about 47

seconds. In exploratory timing, the selected instance \(n=1500\) took

about 1.9 seconds, while \(n=2000\) was still running after 60 seconds and

was interrupted. The recurrence is exponential and highly

instance-dependent. A naive complete sweep through \(2000\) should be

budgeted at several core-hours (rough planning range 5–20 core-hours), not

a few CPU-minutes; a serious extension should use independently checkable

branch certificates or an exact ILP/SAT backend. Such a sweep would still

not address uniformity.

Claim ledger

  • (a) Elementary-rigorous: compression formula (2.1) and its proof; safe

dominance; exhaustive recurrence (4.1); explicit \(n=204\) witness;

partial-summation identity (3.1); implication from a window estimate to the

prime-counting estimate; identification of the exact compressed target.

  • (b) Rigorous-modulo-named-theorem/source: Erdős's primary statements;

Bado's order-of-magnitude result modulo the standard upper-bound sieve; Li's

claimed average, almost-all, and \(2+\varepsilon\) results modulo the

preprint's named Buchstab/beta-sieve inputs.

  • (c) Plausible/structural-unverified: only the negative literature-search

report, the impression that (2.1) is not in the checked sources, and the

diagnosis of what kind of new mechanism is likely needed.

  • (d) Computational-only: live browser observations; document and theorem

location checks; exact optimality for \(2\leq n\leq1000\); timings, state

counts, digests, and direct-program cross-checks.

PARTIAL: Exact radical-support compression proved and a from-scratch rational verifier certifies the sharp bound \(M(n)\leq\sum_{p

This is the AI working report, labelled by outcome — not an independently verified claim unless marked PROVED. ← ledger