Erdős problem #962 (wave 7x)
Access date: 2026-07-28 UTC.
Claim labels
- (a) elementary-rigorous: proved in this report from definitions.
- (b) rigorous-modulo-named-theorem: the elementary deduction is complete, but a specifically named published theorem is used.
- (c) plausible/structural-unverified: heuristic or a reduction with an unproved input.
- (d) computational-only: exhaustively checked in the stated finite range, with reproducible code, but not promoted to an asymptotic theorem.
Result
The main question remains open. The useful new observation is an apparently
unrecorded connection with the Grimm function. It gives the following genuine
improvement to the upper bound recorded on the live page.
> Corollary (b). For all sufficiently large \(n\),
> \[
> k(n)
This follows from Theorem 1(i) of Laishram and Murty, *Grimm's Conjecture
and Smooth Numbers*, Michigan Math. J. 61 (2012), 151--160,
They prove \(g(m) \(0.45<\alpha<0.46\), where \(g(m)\) is the longest prefix \(m+1,\ldots,m+r\) admitting distinct representative prime divisors. Every block in problem #962 automatically has such distinct representatives. The full two-line reduction is proved below. This settles the fixed-power saving which Erdős called a “ridiculously weak result” in 1976, but it does not approach \(\log k(n)\leq(\log n)^{1/2+o(1)}\). The new upper bound only says \(\log k(n)\leq 0.46\log n\). The finite checker also independently certifies The live page was fetched through the Bright Data browser path, including the linked discussion thread, rather than by datacenter > Let \(k(n)\) be the maximal \(k\) such that there exists \(m\leq n\) such that each of the integers > \[
> m+1,\ldots,m+k
> \] > are divisible by at least one prime \(>k\). Estimate \(k(n)\) - in particular, is it true that > \[
> \log k(n) \leq (\log n)^{1/2+o(1)}?
> \] This is copied verbatim from the page's “View the LaTeX source” rendering. The page displayed OPEN, last edited 03 April 2026. It displayed **0 claimed proofs** and the following marker values: | Marker | Live value | |---|---| | Interested in collaborating | None | | Currently working on this problem | None | | I am working on formalising the results | None | Thus the mandatory stop condition did not trigger. The page records the following mathematical results. 1. (b) Erdős [Er65] wrote that \[
\log k(n)\geq(\log n)^{1/2-o(1)}
\] and conjectured \(k(n)=o(n^\epsilon)\), but had no nontrivial upper bound. 2. (b) Erdős [Er76e] obtained \[
\log k(n)\gg\sqrt{\log n\log\log n}
\] and reported \[
k(n)\leq n^{1/2}\exp\!\bigl(-(\log n)^c\bigr)
\] for some \(c>0\), while saying he could not prove \(k(n)\leq n^{1/2-c}\) for a fixed \(c>0\). 3. (b) Tao's comment, using the prime number theorem, proves \(k(n)\leq(1+o(1))n^{1/2}\): if \(k>(1+\epsilon)\sqrt n\), a prime \(\sqrt n
of length \(k\), and that multiple has no prime factor exceeding \(k\). 4. (b) Tang's note proves \[
\log k(n)\geq
\left(\frac1{\sqrt2}-o(1)\right)
\sqrt{\log n\log\log n}.
\] There were five comments, all read before beginning the mathematics: argument just summarized. That issue computes the least starting point for 400 values of \(k\). bound above. route which, if two level-of-distribution/bilinear estimates labelled L5 and L6 held, would give \(k(n)\ll n^{1/e+o(1)}\). (c) The commenter explicitly disclaims a theorem; L5 and L6 are unproved. The numerical normality, kurtosis, and variance observations in that comment are (d) and are not used here. The following sources were opened and checked directly. | Source | What was verified | |---|---| | Erdős, Extremal problems in number theory (1965), p. 183, Problem 5 | The original definition, the lower bound \(k(n)>\exp((\log n)^{1/2-\epsilon})\), the \(o(n^\epsilon)\) conjecture, and the statement that no nontrivial upper bound was known. | | Erdős, Problems and results on consecutive integers (1976), p. 273 | In the inverse notation \(n_k\), the displayed bounds \(n_k | Tang, An Improved Lower Bound on Erdős Problem #962 | The note exists, is two pages, and Theorem 1.2 has the lower-bound constant \(1/\sqrt2\). | | Laishram--Murty, Grimm's Conjecture and Smooth Numbers | The definition of \(g(n)\), Theorem 1(i), and the sentence that \(0.45<\alpha<0.46\) is permissible. | The source-audit mode of the checker downloads these exact PDFs and verifies their SHA-256 hashes, page counts, and extractable theorem phrases. The 1976 PDF is an image-only scan, so its page 273 was additionally inspected visually. The verified hashes are: Targeted searches for the exact problem text, “Erdős Problem 962” together with “Grimm,” the Grimm-function notation \(g(n)\), and all-interval smooth number results found no source that already states the reduction below and no primary source solving the main \(1/2+o(1)\) exponent question. This is a search report, not a claim of bibliographic completeness. The most recent directly relevant paper found was Sarvagya Jain, Existence of Smooth Numbers in Short Intervals, Q. J. Math. 77 (2026), 397--422. (b) Its all-interval theorem requires an interval length at least which is longer than \(\sqrt x\), and hence does not improve the present worst-case exponent. Its much shorter “almost all intervals” result cannot exclude the single exceptional interval needed to define \(k(n)\). For \(m>1\), Laishram and Murty say that \((m,r)\) has a *prime representation* when there are distinct primes and define \(g(m)\) as the largest such \(r\). (a) If \(m+1,\ldots,m+k\) is admissible for problem #962, then Proof. For each \(1\leq i\leq k\), choose a prime \(q_i>k\) dividing \(m+i\). If \(q_i=q_j=q\) for \(i But \(0 and give a prime representation of length \(k\). \(\square\) (b) Laishram--Murty Theorem 1(i) says that there is a permissible \(\alpha\in(0.45,0.46)\) and an \(m_0\) such that \(k(n)\). If \(m\geq m_0\), the lemma gives finite-computation section) gives \(k for \(n\) absorbs this fixed bound as well. Taking the maximum over all \(m\leq n\) proves The arithmetic \(0.46=1/2-1/25\) is checked exactly with rational arithmetic in the verifier. This is asymptotically stronger than Erdős's recorded \(n^{1/2}\exp(-(\log n)^c)=n^{1/2-o(1)}\) upper bound (its constant necessarily has \(0 to zero if \(c\geq1\)). Laishram--Murty Theorem 1(ii) also gives, for fixed \(0<\epsilon<1/3\), By the elementary lemma, (b) This is a rarity statement and does not control the extremal exceptional starting point, so it does not by itself improve \(k(n)\). Let \(P^+(t)\) be the largest prime factor of \(t\), with \(P^+(1)=1\), and define Thus the least problem parameter is \(m=A(k)-1\), and (a) Also \(A(k)\leq A(k+1)\): the first \(k\) terms of a qualifying \((k+1)\)-block qualify as a \(k\)-block. An admissible pair necessarily has \(m\geq k\), since \(m+1\) has a prime factor \(>k\); this also makes the maximum in (1) finite. Two independent sieves agreed on every \(P^+(t)\) through \(1{,}583{,}000\): 1. overwrite every multiple of each prime, processing primes increasingly; 2. construct smallest prime factors with a linear sieve and use \(P^+(t)=\max(\operatorname{spf}(t),P^+(t/\operatorname{spf}(t)))\). For every \(1\leq k\leq122\), the checker then scans every earlier possible start before accepting \(A(k)\). Every accepted block is factored again by plain trial division, a third independent implementation. (d) The exact plateaux are: | \(k\) | \(A(k)\) | \(k\) | \(A(k)\) | |---:|---:|---:|---:| | 1 | 2 | 32--36 | 12013 | | 2 | 5 | 37--38 | 12026 | | 3 | 13 | 39--42 | 17501 | | 4 | 19 | 43--46 | 20833 | | 5 | 55 | 47 | 28225 | | 6 | 65 | 48--51 | 31501 | | 7 | 113 | 52 | 45761 | | 8--9 | 151 | 53--57 | 51521 | | 10 | 226 | 58 | 56701 | | 11 | 364 | 59--60 | 59060 | | 12 | 406 | 61--62 | 72385 | | 13--14 | 736 | 63--70 | 87617 | | 15--16 | 1057 | 71--73 | 136531 | | 17--18 | 1409 | 74--78 | 190651 | | 19--20 | 2059 | 79--85 | 245831 | | 21--27 | 2313 | 86--90 | 341342 | | 28 | 6007 | 91--100 | 381312 | | 29--30 | 6961 | 101--106 | 585916 | | 31 | 10305 | 107 | 585933 | | | | 108 | 741763 | | | | 109--112 | 844361 | | | | 113--121 | 879499 | | | | 122 | 1582081 |Step 0: authoritative live page
curl.Verbatim statement
Status, results, comments, and collision markers
deezel), 02 May 2026: proposes a fourth-momentPrimary-source audit and literature search
Er65 b2dc8978ca143027e8d5940211a71aaf69cde9f2d771499dad881d9fb27878ea
Er76e 5c7d95ca79a407de8b1f2f5ee01e7ad6acdf304cfc587752e213e3bdf57f04fb
LM12 01724c88d7ec1c40ee81745da7a19bc95f180424a4f2aacca37993cbb5d6e8ef
Tang 3db0419ffc8d8c1bb742bb4551e53c8a93207d5b6a60879ed60fd777a6b97327
The Grimm reduction
Lemma
Fixed power saving
A density corollary
Exact finite computation